Benchmarking: HPL (High Performance Linpack)

Script to calculate N

In the HPL.dat file, N is the size of matrix size. This should correspond to roughly 80% of the total memory (across all nodes use for the run). Here's a script to calculate this:

#!/bin/bash
 
if [ $# -ne 2 ]
then
        echo "";
        echo "Usage: $0 [Number of nodes] [Memory per node (Gb)]" >&2;
        echo "Example: $0 32 8";
        exit 1
fi
 
NUM_NODES=$1;
MEM_PER_NODE=$2;
 
echo -e "---------------";
echo -e "[\E[32mNodes\E[39m]: ${NUM_NODES} ";
echo -e "[\E[32mMemory\E[39m]: ${MEM_PER_NODE}Gb";
 
N=`echo "sqrt ( ${NUM_NODES} * ${MEM_PER_NODE} * 0.8 * 100000000)" | bc`
 
echo -e "---------------";
echo -e "[\E[32mN\E[39m]: ${N}";
echo -e "---------------";